derivative of sqrt((1-2x/(1+2x)))

Lösung

\frac{d}{d x} (\frac{1 - 2 x}{1 + 2 x})

- \frac{2}{- 2 x + 1 ( 2 x + 1 ) ^{\frac{3}{2}}}

Schritte zur Lösung

\frac{d}{d x} (\frac{1 - 2 x}{1 + 2 x})

Wende die Kettenregel an:

\frac{1}{2 \frac{1 - 2 x}{1 + 2 x}} \frac{d}{d x} (\frac{1 - 2 x}{1 + 2 x})

= \frac{1}{2 \frac{1 - 2 x}{1 + 2 x}} \frac{d}{d x} (\frac{1 - 2 x}{1 + 2 x})

\frac{d}{d x} (\frac{1 - 2 x}{1 + 2 x}) = - \frac{4}{( 1 + 2 x ) ^{2}}

= \frac{1}{2 \frac{1 - 2 x}{1 + 2 x}} (- \frac{4}{( 1 + 2 x ) ^{2}})

Vereinfache

\frac{1}{2 \frac{1 - 2 x}{1 + 2 x}} (- \frac{4}{( 1 + 2 x ) ^{2}}) : - \frac{2}{- 2 x + 1 ( 2 x + 1 ) ^{\frac{3}{2}}}

= - \frac{2}{- 2 x + 1 ( 2 x + 1 ) ^{\frac{3}{2}}}

\frac{d}{d x} (x^{2} sin (x) - x cos (x))

d er i v a t i v e (3 x^{3} + 2 x) (x - 2) (x + 4)

cos (x) d x - sin (y) d y = 0

\int arcsin (d) x d x

n \to \infty lim (1 - n)