What is the derivative of x^4-8x^2+16 ?

The derivative of x^4-8x^2+16 is 4x^3-16x

What is the first derivative of x^4-8x^2+16 ?

The first derivative of x^4-8x^2+16 is 4x^3-16x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{4} - 8 x^{2} + 16)

4 x^{3} - 16 x

Solution steps

\frac{d}{d x} (x^{4} - 8 x^{2} + 16)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (8 x^{2}) + \frac{d}{d x} (16)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d}{d x} (16) = 0

= 4 x^{3} - 16 x + 0

Simplify

= 4 x^{3} - 16 x

\frac{d}{d y} (\frac{1}{y ^{3}})

\frac{\partial}{\partial x} (2 x^{2} + 5 y^{2} - x y)

\int_{x}^{x^{2}} e^{t^{2}} d t

y = \frac{5 ( 1 - sin ( x ) )}{2 cos ( x )}

tan^{4} (x^{3})

What is the derivative of x^4-8x^2+16 ?
The derivative of x^4-8x^2+16 is 4x^3-16x
What is the first derivative of x^4-8x^2+16 ?
The first derivative of x^4-8x^2+16 is 4x^3-16x