x^'=4x-x^3

Lösung

x^{^{'}} = 4 x - x^{3}

x = \frac{2}{- e ^{- 8 t - c_{1}} + 1}, x = - \frac{2}{- e ^{- 8 t - c_{1}} + 1}

Schritte zur Lösung

x^{'} (t) = 4 x - x^{3}

Solve Bernoulli ODE:

x = \frac{2}{- e ^{- 8 t - c_{1}} + 1}, x = - \frac{2}{- e ^{- 8 t - c_{1}} + 1}

x = \frac{2}{- e ^{- 8 t - c_{1}} + 1}, x = - \frac{2}{- e ^{- 8 t - c_{1}} + 1}

\frac{d}{d x} (\frac{x - 5}{x + 6})

\frac{d}{d x} (b x)

y^{^{'}} = t + 3

\frac{\partial}{\partial x} (\frac{( 3 x + 5 )}{6 y + 1})

\int_{0}^{2} π (4 x^{2} - x^{4}) d x