limit as x approaches 0 of+(sin(x))

解答

x \to 0 lim (+ (sin (x)))

0

求解步骤

x \to 0 lim (sin (x))

代入值

x = 0

= sin (0)

使用以下普通恒等式:

sin (0) = 0

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

t an g e n t f (x) = x + 8, at x = 1

x \to 1 lim (2^{x^{3} - x})

x \to 7 + lim (\frac{( x - 8 )}{x - 7})

\int \frac{1}{1 + 25 x ^{2}} d x

\frac{\partial}{\partial z} (z (1 + e^{x + y}))