y^{''}+2y^'-2y=0

Lösung

y^{^{''}} + 2 y^{^{'}} - 2 y = 0

y = c_{1} e^{(- 1 + 3) t} + c_{2} e^{(- 1 - 3) t}

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) - 2 y = 0

Solve linear ODE:

y = c_{1} e^{(- 1 + 3) t} + c_{2} e^{(- 1 - 3) t}

y = c_{1} e^{(- 1 + 3) t} + c_{2} e^{(- 1 - 3) t}

\frac{d}{d x} (ln (x x^{2} - 3))

\frac{d}{d x} (\frac{2 x + 3}{x + 1})

d er i v a t i v e (3 x^{6} + 8 x^{3})^{4}

\int_{- 1}^{- 0.2588} e^{- i π^{2} w s} d w

k = 2 \sum \infty k^{k}