y^'=(3x-2)^2(30x+29)

Lösung

y^{^{'}} = (3 x - 2)^{2} (30 x + 29)

y = \frac{135 x ^{4}}{2} - 33 x^{3} - 114 x^{2} + 116 x + c_{1}

Schritte zur Lösung

y^{'} (x) = (3 x - 2)^{2} (30 x + 29)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int (3 x - 2)^{2} (30 x + 29) d x

\int (3 x - 2)^{2} (30 x + 29) d x = \frac{135 x ^{4}}{2} - 33 x^{3} - 114 x^{2} + 116 x + c_{1}

y = \frac{135 x ^{4}}{2} - 33 x^{3} - 114 x^{2} + 116 x + c_{1}

t y^{^{'}} + (t + 1) y = 2 t e^{- t}

in v erse l a pl a ce \frac{2 s + 12}{s ^{2} + 6 s + 18}

\int \frac{5 x ^{3} - 4 x}{1 - x ^{4}} d x

\int_{0}^{1} \frac{x - 7}{x ^{2} - 5 x + 6} d x

y^{^{'}} + 6 y = e^{4 t}