What is the derivative of f(x)=x^3+6x^2+x ?

The derivative of f(x)=x^3+6x^2+x is 3x^2+12x+1

What is the first derivative of f(x)=x^3+6x^2+x ?

The first derivative of f(x)=x^3+6x^2+x is 3x^2+12x+1

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derivative of

f (x) = x^{3} + 6 x^{2} + x

3 x^{2} + 12 x + 1

Solution steps

\frac{d}{d x} (x^{3} + 6 x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (6 x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d x}{d x} = 1

= 3 x^{2} + 12 x + 1

y^{^{''}} + 2 y^{^{'}} + 10 y = 3 e^{t} + 1

\int 2050 - 18 x - 4 x^{2} d x

- y^{^{'}} + \frac{4 y}{x} = x^{3} y^{2}

f (x) = \frac{3}{x}, at x = - 4

\int \frac{5 + x + x}{x} d x

What is the derivative of f(x)=x^3+6x^2+x ?
The derivative of f(x)=x^3+6x^2+x is 3x^2+12x+1
What is the first derivative of f(x)=x^3+6x^2+x ?
The first derivative of f(x)=x^3+6x^2+x is 3x^2+12x+1