(9xy^2-3)dx+(9x^2y+4)dy=0

解答

(9 x y^{2} - 3) d x + (9 x^{2} y + 4) d y = 0

y = \frac{- 8 + 64 - 36 x ^{2} ( - 6 x - c _{1} )}{18 x ^{2}}, y = \frac{- 8 - 64 - 36 x ^{2} ( - 6 x - c _{1} )}{18 x ^{2}}

求解步骤

(9 x y^{2} - 3) d x + (9 x^{2} y + 4) d y = 0

求解恰当方程:

y = \frac{- 8 + 64 - 36 x ^{2} ( - 6 x - c _{1} )}{18 x ^{2}}, y = \frac{- 8 - 64 - 36 x ^{2} ( - 6 x - c _{1} )}{18 x ^{2}}

y = \frac{- 8 + 64 - 36 x ^{2} ( - 6 x - c _{1} )}{18 x ^{2}}, y = \frac{- 8 - 64 - 36 x ^{2} ( - 6 x - c _{1} )}{18 x ^{2}}

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