fläche 8-3x,6-x,3

Lösung

fläche

8 - 3 x, 6 - x, 3

\frac{4}{3}

Dezimale

1.33333 \dots

Schritte zur Lösung

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

8 - 3 x = 6 - x : x = 1

8 - 3 x = 3 : x = \frac{5}{3}

6 - x = 3 : x = 3

= \int_{1}^{\frac{5}{3}} ∣ f_{1} (x) - f_{2} (x) ∣ d x + \int_{\frac{5}{3}}^{3} ∣ f_{2} (x) - f_{3} (x) ∣ d x

= \int_{1}^{\frac{5}{3}} ∣ 8 - 3 x - (6 - x) ∣ d x + \int_{\frac{5}{3}}^{3} ∣ 6 - x - 3 ∣ d x

\int_{1}^{\frac{5}{3}} ∣ 8 - 3 x - (6 - x) ∣ d x = \frac{4}{9}

\int_{\frac{5}{3}}^{3} ∣ 6 - x - 3 ∣ d x = \frac{8}{9}

= \frac{4}{9} + \frac{8}{9}

Vereinfache

= \frac{4}{3}

y^{^{''}} - 10 y^{^{'}} + 27 y = 0

\int x^{2} 7 x + 6 d x

\frac{d}{d x} (x^{2} + x y + y^{2} + \frac{3}{x} + \frac{3}{y} + 5)

\int 11 sin (\frac{π t}{12}) + 10 d t

n = 0 \sum \infty 0. 5^{n}