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tangent x+4/x

解答

切线

x + \frac{4}{x}

解答

y = (1 - \frac{4}{a _{0}^{2}}) x + \frac{8}{a _{0}}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, a_{0} + \frac{4}{a _{0}})

计算

y = x + \frac{4}{x}

的斜率:

\frac{d y}{d x} = 1 - \frac{4}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1 - \frac{4}{a _{0}^{2}}

找到斜率 m=

1 - \frac{4}{a _{0}^{2}}

且穿过

(a_{0}, a_{0} + \frac{4}{a _{0}})

的直线:

y = (1 - \frac{4}{a _{0}^{2}}) x + \frac{8}{a _{0}}

y = (1 - \frac{4}{a _{0}^{2}}) x + \frac{8}{a _{0}}

作图

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