What is laplacetransform e^{(-2(t-3))} ?

The answer to laplacetransform e^{(-2(t-3))} is (e^6)/(s+2)

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laplacetransform e^{(-2(t-3))}

laplace transform

e^{(- 2 (t - 3))}

\frac{e ^{6}}{s + 2}

Solution steps

L {e^{(- 2 (t - 3))}}

Expand

e^{- 2 (t - 3)} : e^{- 2 t + 6}

= L {e^{- 2 t + 6}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{6} L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= e^{6} \frac{1}{s + 2}

Refine

e^{6} \frac{1}{s + 2} : \frac{e ^{6}}{s + 2}

= \frac{e ^{6}}{s + 2}

y = x^{3} + 2 x^{2} - 7 x - 5

\int \frac{x ^{4} - 2 x ^{3} + 1}{x ^{2}} d x

f (x) = (3 x)^{2 x}

\frac{( 3 x ^{2} + 2 x + 7 )}{( x + 1 )}

\frac{d}{d x} ((x^{2} + 5 x - 3)^{3})

What is laplacetransform e^{(-2(t-3))} ?
The answer to laplacetransform e^{(-2(t-3))} is (e^6)/(s+2)