normal 5x^2+9y^2=36,(6,4)

解答

法线

5 x^{2} + 9 y^{2} = 36, (6, 4)

5 x^{2} + 9 y^{2} = 36 的法线，切点为 (6, 4)

求解步骤

5 x^{2} + 9 y^{2} = 36 : y = \frac{36 - 5 x ^{2}}{3}, y = - \frac{36 - 5 x ^{2}}{3}

(6, 4)

处的法线的斜率:

m = \frac{- 36 - 5 x ^{2} - 12}{3 ( x - 6 )}

计算

y = \frac{36 - 5 x ^{2}}{3}, y = - \frac{36 - 5 x ^{2}}{3}

的斜率:

m_{y} = \frac{5 x}{3 - 5 x ^{2} + 36}

计算法线的斜率:

m = - \frac{3 - 5 x ^{2} + 36}{5 x}

\frac{d}{d x} (\frac{2 x}{ln ( x )})

x \to 0 lim (x - 5)

\frac{d}{d x} (sin (3) (2 x))

s l o p e 16 4 4 x^{4} + 4

\int sec^{2} (θ) tan^{5} (θ) d θ