xy+y^'=2x,y(0)=5

解答

x y + y^{^{'}} = 2 x, y (0) = 5

y = 3 e^{- \frac{x ^{2}}{2}} + 2

求解步骤

x y + y^{'} (x) = 2 x

求解可分离方程:

y = 3 e^{- \frac{x ^{2}}{2}} + 2

y = 3 e^{- \frac{x ^{2}}{2}} + 2

\frac{d ^{2} y}{d x ^{2}} - 3 \frac{d y}{d x} + 2 y = 4 x^{2}

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