What is (\partial)/(\partial x)(cos(4y-x)) ?

The answer to (\partial)/(\partial x)(cos(4y-x)) is sin(4y-x)

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(\partial)/(\partial x)(cos(4y-x))

\frac{\partial}{\partial x} (cos (4 y - x))

sin (4 y - x)

Solution steps

\frac{\partial}{\partial x} (cos (4 y - x))

Treat

y

as a constant

Apply the chain rule:

- sin (4 y - x) \frac{\partial}{\partial x} (4 y - x)

= - sin (4 y - x) \frac{\partial}{\partial x} (4 y - x)

\frac{\partial}{\partial x} (4 y - x) = - 1

= - sin (4 y - x) (- 1)

Simplify

= sin (4 y - x)

\frac{\partial}{\partial x} (4 y^{x})

9 x - 9 x

\frac{d}{d x} ((x^{2} + y^{2}) sin (\frac{1}{x ^{2} + y ^{2}}))

\int sin (x) in (cos (x)) d x

f (x) = 8 sec (x) tan (x)

What is (\partial)/(\partial x)(cos(4y-x)) ?
The answer to (\partial)/(\partial x)(cos(4y-x)) is sin(4y-x)