(\partial)/(\partial x)(cos(4y-x))

解答

\frac{\partial}{\partial x} (cos (4 y - x))

sin (4 y - x)

求解步骤

\frac{\partial}{\partial x} (cos (4 y - x))

将

y

视为常数

使用连锁律:

- sin (4 y - x) \frac{\partial}{\partial x} (4 y - x)

= - sin (4 y - x) \frac{\partial}{\partial x} (4 y - x)

\frac{\partial}{\partial x} (4 y - x) = - 1

= - sin (4 y - x) (- 1)

化简

= sin (4 y - x)

\frac{\partial}{\partial x} (4 y^{x})

t an g e n t 9 x - 9 x

\frac{d}{d x} ((x^{2} + y^{2}) sin (\frac{1}{x ^{2} + y ^{2}}))

\int sin (x) in (cos (x)) d x

d er i v a t i v e f (x) = 8 sec (x) tan (x)