derivative of (2x+7/(2x))

解

\frac{d}{d x} (\frac{2 x + 7}{2 x})

- \frac{7}{2 x ^{2}}

解答ステップ

\frac{d}{d x} (\frac{2 x + 7}{2 x})

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{2 x + 7}{x})

商の法則を適用:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{2} \cdot \frac{\frac{d}{d x} ( 2 x + 7 ) x - \frac{d x}{d x} ( 2 x + 7 )}{x ^{2}}

\frac{d}{d x} (2 x + 7) = 2

\frac{d x}{d x} = 1

= \frac{1}{2} \cdot \frac{2 x - 1 \cdot ( 2 x + 7 )}{x ^{2}}

簡素化

\frac{1}{2} \cdot \frac{2 x - 1 \cdot ( 2 x + 7 )}{x ^{2}} : - \frac{7}{2 x ^{2}}

= - \frac{7}{2 x ^{2}}