derivative f(t)=3t^3-2/(t^2)

Lösung

ableitung von

f (t) = 3 t^{3} - \frac{2}{t ^{2}}

9 t^{2} + \frac{4}{t ^{3}}

Schritte zur Lösung

\frac{d}{d t} (3 t^{3} - \frac{2}{t ^{2}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3 t^{3}) - \frac{d}{d t} (\frac{2}{t ^{2}})

\frac{d}{d t} (3 t^{3}) = 9 t^{2}

\frac{d}{d t} (\frac{2}{t ^{2}}) = - \frac{4}{t ^{3}}

= 9 t^{2} - (- \frac{4}{t ^{3}})

Vereinfache

= 9 t^{2} + \frac{4}{t ^{3}}

x \to 0 + lim (\frac{1}{2 x ^{2}})

d er i v a t i v e 3 + 5 x

\frac{d}{d x} (x + y z)

d er i v a t i v e 9 e^{x} + \frac{8}{3 x}

l a pl a ce t r an s f or m 1.5 - 1.5 e^{- t}