What is the integral from 1 to 7 of 2/(x^3) ?

The integral from 1 to 7 of 2/(x^3) is 48/49

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integral from 1 to 7 of 2/(x^3)

\int_{1}^{7} \frac{2}{x ^{3}} d x

\frac{48}{49}

Decimal Notation

0.97959 \dots

Solution steps

\int_{1}^{7} \frac{2}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{7} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{7}

= 2 [- \frac{1}{2 x ^{2}}]_{1}^{7}

Compute the boundaries:

\frac{24}{49}

= 2 \cdot \frac{24}{49}

Simplify

= \frac{48}{49}

tan (\frac{x}{2})

sin (3 x)

\int (cos^{4} (x)) d x

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\int_{π}^{2 π} sin^{2} (x) d x

What is the integral from 1 to 7 of 2/(x^3) ?
The integral from 1 to 7 of 2/(x^3) is 48/49