y^'=(x+y-3)^2

Lösung

y^{^{'}} = (x + y - 3)^{2}

y = tan (x + c_{1}) - x + 3

Schritte zur Lösung

y^{'} (x) = (x + y - 3)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x + 3

y = tan (x + c_{1}) - x + 3

\int - x tan (x) d x

x \to 1 lim (2 x^{2} - 5 x - 1)

l a pl a ce t r an s f or m 6 e^{- 5 t} + e^{3 t} + 5 t^{3} - 9

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