tangent f(x)= 1/(5+3x),(2, 1/11)

解答

切线

f (x) = \frac{1}{5 + 3 x}, (2, \frac{1}{11})

y = - \frac{3}{121} x + \frac{17}{121}

求解步骤

计算

f (x) = \frac{1}{5 + 3 x}

的斜率:

\frac{df ( x )}{d x} = - \frac{3}{( 5 + 3 x ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{121}

找到斜率 m=

- \frac{3}{121}

且穿过

(2, \frac{1}{11})

的直线:

y = - \frac{3}{121} x + \frac{17}{121}

y = - \frac{3}{121} x + \frac{17}{121}

\int_{1}^{2} 8 r^{2} ln (r) d r

\int 3 t + 2 d t

t an g e n t f (x) = \frac{x ^{3}}{3} - \frac{3}{x ^{3}}, at x = - 1

d er i v a t i v e f (x) = (\frac{2 x}{7} + 1)

\int x^{2} sin^{2} (x) d x