d/(dt)(sqrt(3t+1))

解答

\frac{d}{d t} (3 t + 1)

\frac{3}{2 3 t + 1}

求解步骤

\frac{d}{d t} (3 t + 1)

使用连锁律:

\frac{1}{2 3 t + 1} \frac{d}{d t} (3 t + 1)

= \frac{1}{2 3 t + 1} \frac{d}{d t} (3 t + 1)

\frac{d}{d t} (3 t + 1) = 3

= \frac{1}{2 3 t + 1} \cdot 3

化简

\frac{1}{2 3 t + 1} \cdot 3 : \frac{3}{2 3 t + 1}

= \frac{3}{2 3 t + 1}

\int - t ln (t) d t

t an g e n t x^{2}, at x = 0

\frac{\partial}{\partial y} (x^{3} y z^{2})

\int [\frac{4}{16 x ^{2} + 1}] d x

t an g e n t f (x) = x^{2} - 5 x + 5, (6, 11)