y^'+5y=e^{(-2x)}

Lösung

y^{^{'}} + 5 y = e^{(- 2 x)}

y = \frac{1}{3 e ^{2 x}} + \frac{c _{1}}{e ^{5 x}}

Schritte zur Lösung

y^{'} (x) + 5 y = e^{(- 2 x)}

Solve linear ODE:

y = \frac{1}{3 e ^{2 x}} + \frac{c _{1}}{e ^{5 x}}

y = \frac{1}{3 e ^{2 x}} + \frac{c _{1}}{e ^{5 x}}

d er i v a t i v e p (θ) = 3 θ

d er i v a t i v e y = (x + 1)^{x}

\int_{0}^{2} 2 π x (2 x^{2} - x^{3}) d x

\int \frac{1}{( a + b ) - ( a - b ) x ^{2}} d x

\int \frac{22}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x