(1/(x-1))^'

Lösung

(\frac{1}{x - 1})^{^{'}}

- \frac{1}{( x - 1 ) ^{2}}

Schritte zur Lösung

(\frac{1}{x - 1})^{'}

Wende Exponentenregel an:

\frac{1}{a} = a^{- 1}

= ((x - 1)^{- 1})^{^{'}}

Wende die Kettenregel an:

- \frac{1}{( x - 1 ) ^{2}} (x - 1)^{'}

= - \frac{1}{( x - 1 ) ^{2}} (x - 1)^{'}

(x - 1)^{'} = 1

= - \frac{1}{( x - 1 ) ^{2}} \cdot 1

Vereinfache

= - \frac{1}{( x - 1 ) ^{2}}

l a pl a ce t r an s f or m t cos (3 t) + 2 e^{- 4 t}

\int e^{- 3 x} sin (5 x) d x

\frac{d}{d x} (\frac{c ^{9} - x ^{9}}{c ^{9} + x ^{9}})

\int (\frac{1}{x ^{1.2}}) d x

x \to 0 lim ((- ln (x))^{x})