integral of \sqrt[3]{x}-1

Lösung

\int 3 x - 1 d x

\frac{3}{4} x^{\frac{4}{3}} - x + C

Schritte zur Lösung

\int 3 x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x d x - \int 1 d x

\int 3 x d x = \frac{3}{4} x^{\frac{4}{3}}

\int 1 d x = x

= \frac{3}{4} x^{\frac{4}{3}} - x

Füge eine Konstante zur Lösung hinzu

= \frac{3}{4} x^{\frac{4}{3}} - x + C

\frac{\partial}{\partial x} (ln (3 x + 4 y))

\frac{\partial}{\partial x} (x^{3} - 9 x y + y^{3} - 2)

\int_{1}^{e} \frac{sec ( 2 + ln ( x ) )}{x} d x

\int e^{2 x + l n (x)} d x

x \to 7 - lim (\frac{1}{x ^{2} ( x + 7 )})