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Beliebt Rechnen >

y^'=(2x)/(1+2y),y(2)=1

Lösung

y^{^{'}} = \frac{2 x}{1 + 2 y}, y (2) = 1

Lösung

y = \frac{- 1 + 4 x ^{2} - 7}{2}

Schritte zur Lösung

y^{'} (x) = \frac{2 x}{1 + 2 y}

Solve separable ODE:

y = \frac{- 1 + 4 x ^{2} - 7}{2}

y = \frac{- 1 + 4 x ^{2} - 7}{2}

Graph

Beliebte Beispiele

integral from 1 to infinity of e^{-st}

\int_{1}^{\infty} e^{- s t} d t

inverselaplace 1/((s^2+1)(s^2+4))

in v erse l a pl a ce \frac{1}{( s ^{2} + 1 ) ( s ^{2} + 4 )}

x((dy)/(dx))=((1-4y^2))/(3y)

x (\frac{d y}{d x}) = \frac{( 1 - 4 y ^{2} )}{3 y}

xsqrt(x)+x^2sqrt(x)

x x + x^{2} x

(\partial)/(\partial x)(5/x)

\frac{\partial}{\partial x} (\frac{5}{x})