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受欢迎的微积分 >

integral of 4/(x^2-4x+20)

解答

\int \frac{4}{x ^{2} - 4 x + 20} d x

解答

arctan (\frac{1}{4} (x - 2)) + C

求解步骤

\int \frac{4}{x ^{2} - 4 x + 20} d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{x ^{2} - 4 x + 20} d x

对

x^{2} - 4 x + 20

配方:

(x - 2)^{2} + 16

= 4 \cdot \int \frac{1}{( x - 2 ) ^{2} + 16} d x

使用换元积分法

= 4 \cdot \int \frac{1}{u ^{2} + 16} d u

使用换元积分法

= 4 \cdot \int \frac{1}{4 ( v ^{2} + 1 )} d v

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{4} \cdot \int \frac{1}{v ^{2} + 1} d v

使用积分常见定则:

\int \frac{1}{v ^{2} + 1} d v = arctan (v)

= 4 \cdot \frac{1}{4} arctan (v)

代回

= 4 \cdot \frac{1}{4} arctan (\frac{x - 2}{4})

化简

4 \cdot \frac{1}{4} arctan (\frac{x - 2}{4}) : arctan (\frac{1}{4} (x - 2))

= arctan (\frac{1}{4} (x - 2))

解答补常数

= arctan (\frac{1}{4} (x - 2)) + C

作图

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