(\partial ^2)/(\partial x^2)(x^3+3xy^2)

解答

\frac{\partial ^{2}}{\partial x ^{2}} (x^{3} + 3 x y^{2})

6 x

求解步骤

\frac{\partial ^{2}}{\partial x ^{2}} (x^{3} + 3 x y^{2})

\frac{\partial}{\partial x} (x^{3} + 3 x y^{2}) = 3 x^{2} + 3 y^{2}

= \frac{\partial}{\partial x} (3 x^{2} + 3 y^{2})

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2}) = 6 x

= 6 x

in v erse l a pl a ce \frac{1}{( s - 3 ) ^{3}}

\frac{d v}{d t} = - k t v^{2}

d er i v a t i v e f (x) = 15 x ln (8 x)

\frac{\partial}{\partial x} (- 6 + 5 - 6 x)

\frac{d}{d x} (\frac{2}{x + 3})