integral from 0 to 4 of (2x+3)

Lösung

\int_{0}^{4} (2 x + 3) d x

28

Schritte zur Lösung

\int_{0}^{4} 2 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 x d x + \int_{0}^{4} 3 d x

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 3 d x = 12

= 16 + 12

Vereinfache

= 28

\frac{d}{d x} (ln (\frac{x ^{2} + 1}{x + 1}))

t an g e n t f (x) = (x^{3} - 9 x)^{12}, at x = 3

d er i v a t i v e \frac{9}{t ^{4}}

\int \frac{2 x}{3 x ^{2} + 1} d x

\int_{- 5}^{5} (4 - ∣ x ∣) d x