derivative ln(e^{7x-2})

Lösung

ableitung von

ln (e^{7 x - 2})

7

Schritte zur Lösung

\frac{d}{d x} (ln (e^{7 x - 2}))

Vereinfache

ln (e^{7 x - 2}) : 7 x - 2

= \frac{d}{d x} (7 x - 2)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 x) - \frac{d}{d x} (2)

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (2) = 0

= 7 - 0

Vereinfache

= 7

y^{^{''}} + 4 y^{^{'}} + 10 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\frac{d}{d x} (\frac{1}{2 + cos ( x )})

\int 4 e^{x} cos (2 x) d x

t an g e n t f (x) = (1 + 3 x) (5 - 2 x), at x = 2

in v erse l a pl a ce \frac{s}{( s + 1 ) ( s ^{2} + 4 )}