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Beliebt Rechnen >

24y^{''}+12y^'=0,y(3)=-3,y^'(-4)=4

Lösung

24 y^{^{''}} + 12 y^{^{'}} = 0, y (3) = - 3, y^{^{'}} (- 4) = 4

Lösung

y = - 3 + \frac{8}{e ^{\frac{7}{2}}} - 8 e^{\frac{- t - 4}{2}}

Schritte zur Lösung

24 y^{''} (t) + 12 y^{'} (t) = 0

Solve linear ODE:

y = - 3 + \frac{8}{e ^{\frac{7}{2}}} - 8 e^{\frac{- t - 4}{2}}

y = - 3 + \frac{8}{e ^{\frac{7}{2}}} - 8 e^{\frac{- t - 4}{2}}

Graph

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