x^{''}+ax=0

Lösung

x^{^{''}} + a x = 0

x = c_{1} cos (a t) + c_{2} sin (a t)

Schritte zur Lösung

x^{''} (t) + a x = 0

Solve linear ODE:

x = c_{1} cos (a t) + c_{2} sin (a t)

x = c_{1} cos (a t) + c_{2} sin (a t)

16 y^{^{''}} + 24 y^{^{'}} + 9 y = 0

\int 6 r 4 - r^{2} d r

\frac{d y}{d x} = e^{x + 2 y}

\frac{d y}{d x} = y (y + 2)

f (x) = 2 \cdot x