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Beliebt Rechnen >

laplacetransform 6cos(4t-1)

Lösung

laplace transformation

6 cos (4 t - 1)

Lösung

\frac{6 ( cos ( 1 ) s + 4 sin ( 1 ) )}{s ^{2} + 16}

Schritte zur Lösung

L {6 cos (4 t - 1)}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 6 L {cos (4 t - 1)}

L {cos (4 t - 1)} : \frac{cos ( 1 ) s + 4 sin ( 1 )}{s ^{2} + 16}

= 6 \cdot \frac{cos ( 1 ) s + 4 sin ( 1 )}{s ^{2} + 16}

Fasse

6 \frac{cos ( 1 ) s + 4 sin ( 1 )}{s ^{2} + 16}

zusammen:

\frac{6 ( cos ( 1 ) s + 4 sin ( 1 ) )}{s ^{2} + 16}

= \frac{6 ( cos ( 1 ) s + 4 sin ( 1 ) )}{s ^{2} + 16}

Beliebte Beispiele

integral from 0 to 3 of-2x

\int_{0}^{3} - 2 x d x

tangent f(x)=x^4+9e^x,\at x=0

t an g e n t f (x) = x^{4} + 9 e^{x}, at x = 0

integral of (x^2)/(2^x)

\int \frac{x ^{2}}{2 ^{x}} d x

(\partial)/(\partial x)((2+4y^2)x-3x^2)

\frac{\partial}{\partial x} ((2 + 4 y^{2}) x - 3 x^{2})

integral of (sqrt(x^2+5))/x

\int \frac{x ^{2} + 5}{x} d x