derivative 14*((-x+2)/(x^2))

Lösung

ableitung von

14 \cdot (\frac{- x + 2}{x ^{2}})

- \frac{14 ( - x + 4 )}{x ^{3}}

Schritte zur Lösung

\frac{d}{d x} (14 \cdot \frac{- x + 2}{x ^{2}})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 14 \frac{d}{d x} (\frac{- x + 2}{x ^{2}})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 14 \cdot \frac{\frac{d}{d x} ( - x + 2 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( - x + 2 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (- x + 2) = - 1

\frac{d}{d x} (x^{2}) = 2 x

= 14 \cdot \frac{( - 1 ) x ^{2} - 2 x ( - x + 2 )}{( x ^{2} ) ^{2}}

Vereinfache

14 \cdot \frac{( - 1 ) x ^{2} - 2 x ( - x + 2 )}{( x ^{2} ) ^{2}} : - \frac{14 ( - x + 4 )}{x ^{3}}

= - \frac{14 ( - x + 4 )}{x ^{3}}

\int e^{3 y} d y

l a pl a ce t r an s f or m e^{- 3 t} sin (t)

\frac{d y}{d x} = (\frac{- 2 y}{( x - 2 )})

x \to 0 + lim (- 1)

\int 6 (x + 2) d x