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Beliebt Rechnen >

4ty^'+4=5+t

Lösung

4 t y^{^{'}} + 4 = 5 + t

Lösung

y = \frac{1}{4} (t + ln (t)) + c_{1}

Schritte zur Lösung

4 t y^{'} (t) + 4 = 5 + t

Isoliere

y^{'} (t) : y^{'} (t) = \frac{t + 1}{4 t}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{t + 1}{4 t} d t

\int \frac{t + 1}{4 t} d t = \frac{1}{4} (t + ln (t)) + c_{1}

y = \frac{1}{4} (t + ln (t)) + c_{1}

Graph

Beliebte Beispiele

limit as x approaches 0 of 0^0

x \to 0 lim (0^{0})

derivative f(x)=(x^2)/(x+3)

d er i v a t i v e f (x) = \frac{x ^{2}}{x + 3}

(\partial)/(\partial x)(4xy+3yz+5xy-48)

\frac{\partial}{\partial x} (4 x y + 3 yz + 5 x y - 48)

derivative of x^nln(1/x)

\frac{d}{d x} (x^{n} ln (\frac{1}{x}))

inverselaplace (-3)/((s-2)^2)

in v erse l a pl a ce \frac{- 3}{( s - 2 ) ^{2}}