integral from-4 to 0 of |x+2|

解答

\int_{- 4}^{0} ∣ x + 2 ∣ d x

4

求解步骤

\int_{- 4}^{0} ∣ x + 2 ∣ d x

拿掉绝对值

= \int_{- 4}^{- 2} - x - 2 d x + \int_{- 2}^{0} x + 2 d x

\int_{- 4}^{- 2} - x - 2 d x = 2

\int_{- 2}^{0} x + 2 d x = 2

= 2 + 2

化简

= 4

\frac{\partial}{\partial x} (4 - x^{2} - 2 y^{2})

\frac{d}{d x} (A x^{2} e^{3 x})

x \frac{d y}{d x} = 3 x e^{x} - y + 6 x^{2}

x \to 1 lim (x^{\frac{4}{1 - x}})

\int - x^{2} + 25 d x