y^{''}+16y=2tan(4x)

Lösung

y^{^{''}} + 16 y = 2 tan (4 x)

y = c_{1} cos (4 x) + c_{2} sin (4 x) + \frac{- 2 cos ( 4 x ) ( ln ( tan ( 4 x ) + sec ( 4 x ) ) - sin ( 4 x ) ) - sin ( 8 x )}{16}

Schritte zur Lösung

y^{''} (x) + 16 y = 2 tan (4 x)

Solve linear ODE:

y = c_{1} cos (4 x) + c_{2} sin (4 x) + \frac{- 2 cos ( 4 x ) ( ln ( tan ( 4 x ) + sec ( 4 x ) ) - sin ( 4 x ) ) - sin ( 8 x )}{16}

y = c_{1} cos (4 x) + c_{2} sin (4 x) + \frac{- 2 cos ( 4 x ) ( ln ( tan ( 4 x ) + sec ( 4 x ) ) - sin ( 4 x ) ) - sin ( 8 x )}{16}

x \to - 1 lim (2 x)

\int_{0}^{π} cos (n x) d x

\int_{0}^{e} ln (x^{2}) d x

\int_{- 1}^{1} (3 x - 2) d x

t an g e n t y = \frac{3}{x}