What is the sum from n=1 to infinity of (n-5)/(n+5) ?

The sum from n=1 to infinity of (n-5)/(n+5) is diverges

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sum from n=1 to infinity of (n-5)/(n+5)

n = 1 \sum \infty \frac{n - 5}{n + 5}

diverges

Solution steps

n = 1 \sum \infty \frac{n - 5}{n + 5}

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d x} (x^{2} + y^{2} - 5)

s l o p e \frac{4 x}{x - 5}

\frac{d x}{d r} + e^{r - x} = 0

\frac{\partial}{\partial x} (e^{8 y} sin (- 8 x))

\int x (sin (x))^{2} d x

What is the sum from n=1 to infinity of (n-5)/(n+5) ?
The sum from n=1 to infinity of (n-5)/(n+5) is diverges