What is the derivative of 3/(8x^{5/2)} ?

The derivative of 3/(8x^{5/2)} is -(15)/(16x^{7/2)}

What is the first derivative of 3/(8x^{5/2)} ?

The first derivative of 3/(8x^{5/2)} is -(15)/(16x^{7/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

\frac{3}{8 x ^{\frac{5}{2}}}

- \frac{15}{16 x ^{\frac{7}{2}}}

Solution steps

\frac{d}{d x} (\frac{3}{8 x ^{\frac{5}{2}}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3}{8} \frac{d}{d x} (\frac{1}{x ^{\frac{5}{2}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{3}{8} \frac{d}{d x} (x^{- \frac{5}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{3}{8} (- \frac{5}{2} x^{- \frac{5}{2} - 1})

Simplify

\frac{3}{8} (- \frac{5}{2} x^{- \frac{5}{2} - 1}) : - \frac{15}{16 x ^{\frac{7}{2}}}

= - \frac{15}{16 x ^{\frac{7}{2}}}

\frac{d}{d x} (4 x y^{3})

t an g e n t x (9.3)

y^{^{'}} = - \frac{y}{t} + 2

a re a f (x) = x^{4} - 4 x^{2}, g (x) = x^{2} - 4

\int (6 x + 2) d x

What is the derivative of 3/(8x^{5/2)} ?
The derivative of 3/(8x^{5/2)} is -(15)/(16x^{7/2)}
What is the first derivative of 3/(8x^{5/2)} ?
The first derivative of 3/(8x^{5/2)} is -(15)/(16x^{7/2)}