y^'=(x^2)/(y(2+x^3))

Lösung

y^{^{'}} = \frac{x ^{2}}{y ( 2 + x ^{3} )}

y = \frac{2 ln ( 2 + x ^{3} ) + c _{1}}{3}, y = - \frac{2 ln ( 2 + x ^{3} ) + c _{1}}{3}

Schritte zur Lösung

y^{'} (x) = \frac{x ^{2}}{y ( 2 + x ^{3} )}

Solve separable ODE:

y = \frac{2 ln ( 2 + x ^{3} ) + c _{1}}{3}, y = - \frac{2 ln ( 2 + x ^{3} ) + c _{1}}{3}

y = \frac{2 ln ( 2 + x ^{3} ) + c _{1}}{3}, y = - \frac{2 ln ( 2 + x ^{3} ) + c _{1}}{3}

\frac{\partial}{\partial x} (3 e^{x} cos (y))

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\frac{\partial}{\partial x} (- \frac{9 x ^{2}}{x ^{2} + y ^{2}})

\int_{4}^{4} e^{- x^{2}} d x

\frac{d}{d y} (3 x + 4 y)