(dy)/(dx)=y(1+x)^{-1}

Lösung

\frac{d y}{d x} = y (1 + x)^{- 1}

y = e^{c_{1}} + e^{c_{1}} x

Schritte zur Lösung

\frac{d y}{d x} = y (1 + x)^{- 1}

Solve separable ODE:

y = e^{c_{1}} + e^{c_{1}} x

y = e^{c_{1}} + e^{c_{1}} x

\int \frac{1}{( x + 3 ) ( x + 5 )} d x

\frac{\partial}{\partial x} ((5 x - x^{2}) cos (t))

in v erse l a pl a ce Y (s) = \frac{s - 2}{s ^{2} - 2 s - 3}

t an g e n t f (x) = - 3 x^{2} + x + 2, at x = 1

\frac{\partial}{\partial x} (\frac{p}{1 + e ^{c o s (x)}})