What is the derivative of y=4x^2+3x ?

The derivative of y=4x^2+3x is 8x+3

What is the first derivative of y=4x^2+3x ?

The first derivative of y=4x^2+3x is 8x+3

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derivative of

y = 4 x^{2} + 3 x

8 x + 3

Solution steps

\frac{d}{d x} (4 x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3 x) = 3

= 8 x + 3

a re a 1 - x^{2}, x^{2} - 3, x + 3

\frac{\partial}{\partial x} (2 (ln (x)) + y)

\frac{\partial}{\partial x} (x (x - 2))

\int \frac{1}{x ( x + 1 )} d x

ma c l a u r in 2 x e^{x^{2}}

What is the derivative of y=4x^2+3x ?
The derivative of y=4x^2+3x is 8x+3
What is the first derivative of y=4x^2+3x ?
The first derivative of y=4x^2+3x is 8x+3