What is the d/(dθ)(4cos(3θ)) ?

The d/(dθ)(4cos(3θ)) is -12sin(3θ)

What is the first d/(dθ)(4cos(3θ)) ?

The first d/(dθ)(4cos(3θ)) is -12sin(3θ)

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\frac{d}{d θ} (4 cos (3 θ))

- 12 sin (3 θ)

Solution steps

\frac{d}{d θ} (4 cos (3 θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d θ} (cos (3 θ))

Apply the chain rule:

- sin (3 θ) \frac{d}{d θ} (3 θ)

= - sin (3 θ) \frac{d}{d θ} (3 θ)

\frac{d}{d θ} (3 θ) = 3

= 4 (- sin (3 θ) \cdot 3)

Simplify

= - 12 sin (3 θ)

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