derivative θcos(θ)+sin(θ)

Lösung

ableitung von

θ cos (θ) + sin (θ)

- θ sin (θ) + 2 cos (θ)

Schritte zur Lösung

\frac{d}{d θ} (θ cos (θ) + sin (θ))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (θ cos (θ)) + \frac{d}{d θ} (sin (θ))

\frac{d}{d θ} (θ cos (θ)) = cos (θ) - θ sin (θ)

\frac{d}{d θ} (sin (θ)) = cos (θ)

= cos (θ) - θ sin (θ) + cos (θ)

Vereinfache

= - θ sin (θ) + 2 cos (θ)

\int_{6}^{8} \frac{98}{( x - 6 ) ^{3}} d x

x \to 2 lim (- 1.999 + 2)

t an g e n t f (x) = - x^{2} + 4 x

\int \frac{10 x - 2}{5 x ^{2} - 2 x} d x

\int \frac{( 1 + sin ( x ) )}{cos ^{2} ( x )} d x