e^xy^'-e^xy=1-2x

解答

e^{x} y^{^{'}} - e^{x} y = 1 - 2 x

y = \frac{x}{e ^{x}} + c_{1} e^{x}

求解步骤

e^{x} y^{'} (x) - e^{x} y = 1 - 2 x

求解线性方程:

y = \frac{x}{e ^{x}} + c_{1} e^{x}

y = \frac{x}{e ^{x}} + c_{1} e^{x}

\int \frac{e ^{4 t}}{t} d t

in v erse l a pl a ce \frac{s - 1}{s ^{2} ( s ^{2} + 1 )}

\frac{d}{d x} (\frac{4 x ^{2} + 6 x + 4}{x})

x \to 7 lim (\frac{∣ x - 7 ∣}{x - 7})

x y^{^{'}} + y = 3 x^{2}