x^{''}=k^2x

Lösung

x^{^{''}} = k^{2} x

x = c_{1} e^{k t} + c_{2} e^{- k t}

Schritte zur Lösung

x^{''} (t) = k^{2} x

Solve linear ODE:

x = c_{1} e^{k t} + c_{2} e^{- k t}

x = c_{1} e^{k t} + c_{2} e^{- k t}

\frac{\partial}{\partial x} (x \cdot sin (x^{2} - y^{2}))

\int_{- 2}^{2} \frac{1}{∣ 2 x ∣} d x

\int_{- \infty}^{\infty} \frac{1}{e ^{x} + e ^{- x}} d x

d er i v a t i v e f (x) = x^{13}

\frac{d}{d x} (\frac{x ^{3} + x - 1}{2})