derivative of sqrt(7x^3+4)

Lösung

\frac{d}{d x} (7 x^{3} + 4)

\frac{21 x ^{2}}{2 7 x ^{3} + 4}

Schritte zur Lösung

\frac{d}{d x} (7 x^{3} + 4)

Wende die Kettenregel an:

\frac{1}{2 7 x ^{3} + 4} \frac{d}{d x} (7 x^{3} + 4)

= \frac{1}{2 7 x ^{3} + 4} \frac{d}{d x} (7 x^{3} + 4)

\frac{d}{d x} (7 x^{3} + 4) = 21 x^{2}

= \frac{1}{2 7 x ^{3} + 4} \cdot 21 x^{2}

Vereinfache

\frac{1}{2 7 x ^{3} + 4} \cdot 21 x^{2} : \frac{21 x ^{2}}{2 7 x ^{3} + 4}

= \frac{21 x ^{2}}{2 7 x ^{3} + 4}

\int \frac{18}{x ^{2} + 4 x - 5} d x

in v erse l a pl a ce \frac{1}{( s ^{3} + 1 ) ( s ^{2} + 1 )}

d er i v a t i v e x^{2} ln (4 x + 3)

\int x sin (π x) d x

\frac{\partial}{\partial x} (k ln (x^{2} + y^{2}))