integral from 0 to 1 of (1-x)

Lösung

\int_{0}^{1} (1 - x) d x

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

\int_{0}^{1} 1 - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d x - \int_{0}^{1} x d x

\int_{0}^{1} 1 d x = 1

\int_{0}^{1} x d x = \frac{1}{2}

= 1 - \frac{1}{2}

Vereinfache

1 - \frac{1}{2} : \frac{1}{2}

= \frac{1}{2}

\int \frac{4 x ^{2}}{3 3 + 5 x} d x

\frac{d}{d x} (5 x^{2} + 4 sin (x))

n = 0 \sum \infty (\frac{n}{n + 2})^{n}

11 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 8

x \to 2 lim (\frac{5}{x})