(\partial)/(\partial x)(e^x+cos(xy))

解答

\frac{\partial}{\partial x} (e^{x} + cos (x y))

e^{x} - sin (x y) y

求解步骤

\frac{\partial}{\partial x} (e^{x} + cos (x y))

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x}) + \frac{\partial}{\partial x} (cos (x y))

\frac{\partial}{\partial x} (e^{x}) = e^{x}

\frac{\partial}{\partial x} (cos (x y)) = - sin (x y) y

= e^{x} - sin (x y) y

\frac{d}{d x} (- x^{2} - 2)

\int \frac{2 x}{9 - x ^{4}} d x

s l o p e (- 3, 1), (- 7, - 2)

d er i v a t i v e (sec (x))^{3}

\int \frac{e ^{x}}{( e ^{x} - 8 ) ( e ^{2 x} + 1 )} d x