What is the integral of cos(x)e^x ?

The integral of cos(x)e^x is (e^xsin(x))/2+(e^xcos(x))/2+C

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integral of cos(x)e^x

\int cos (x) e^{x} d x

\frac{e ^{x} sin ( x )}{2} + \frac{e ^{x} cos ( x )}{2} + C

Solution steps

\int cos (x) e^{x} d x

Apply Integration By Parts

: e^{x} sin (x) - \int e^{x} sin (x) d x

= e^{x} sin (x) - \int e^{x} sin (x) d x

Apply Integration By Parts

: - e^{x} cos (x) - \int - e^{x} cos (x) d x

= e^{x} sin (x) - (- e^{x} cos (x) - \int - e^{x} cos (x) d x)

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{x} sin (x) - (- e^{x} cos (x) - (- \int e^{x} cos (x) d x))

Therefore

\int e^{x} cos (x) d x = e^{x} sin (x) - (- e^{x} cos (x) - (- \int e^{x} cos (x) d x))

Isolate

\int e^{x} cos (x) d x

= \frac{e ^{x} sin ( x )}{2} + \frac{e ^{x} cos ( x )}{2}

Add a constant to the solution

= \frac{e ^{x} sin ( x )}{2} + \frac{e ^{x} cos ( x )}{2} + C

\int \frac{4 x ^{2} - 7 x - 19}{x ^{2} - 2 x - 3} d x

- 3 a e^{- 3 x} + b e^{x} + c (e^{x} + e^{x} x)

\frac{1}{2} (e^{(1 - x)})

y = - \frac{12}{7} x = + b

\frac{d}{d x} y = tan^{2} (x)

What is the integral of cos(x)e^x ?
The integral of cos(x)e^x is (e^xsin(x))/2+(e^xcos(x))/2+C