derivative y=ln(xln(x))

解答

导数

y = ln (x ln (x))

\frac{ln ( x ) + 1}{x ln ( x )}

求解步骤

\frac{d}{d x} (ln (x ln (x)))

使用连锁律:

\frac{1}{x ln ( x )} \frac{d}{d x} (x ln (x))

= \frac{1}{x ln ( x )} \frac{d}{d x} (x ln (x))

\frac{d}{d x} (x ln (x)) = ln (x) + 1

= \frac{1}{x ln ( x )} (ln (x) + 1)

化简

\frac{1}{x ln ( x )} (ln (x) + 1) : \frac{ln ( x ) + 1}{x ln ( x )}

= \frac{ln ( x ) + 1}{x ln ( x )}

\int sec^{5} (t) d t

\frac{\partial ^{2}}{\partial x ^{2}} (x^{2} - e^{y^{2}})

d er i v a t i v e ln ∣ sec (θ) + tan (θ) ∣

\int_{0}^{1} \frac{x ^{4} + 2}{x} d x

d er i v a t i v e \frac{s - 1}{s + 1}