xy^'+15y=0

Lösung

x y^{^{'}} + 15 y = 0

y = \frac{c _{1}}{x ^{15}}

Schritte zur Lösung

x y^{'} (x) + 15 y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{15}}

y = \frac{c _{1}}{x ^{15}}

\frac{d}{d x} (sin (3 x^{3}))

\int \frac{2 x - 13}{x ^{2} - 13 x + 50} d x

y^{^{'}} + 0.564 y^{2} = 0

\frac{\partial}{\partial x} (4 x z sin (y))

n = 2 \sum \infty \frac{6}{n ^{2} - 1}